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4.9x^2+4.75x=0
a = 4.9; b = 4.75; c = 0;
Δ = b2-4ac
Δ = 4.752-4·4.9·0
Δ = 22.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.75)-\sqrt{22.5625}}{2*4.9}=\frac{-4.75-\sqrt{22.5625}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.75)+\sqrt{22.5625}}{2*4.9}=\frac{-4.75+\sqrt{22.5625}}{9.8} $
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